tolongin, butuh urgent malem ini jugaa
makasiuww
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poin uda cukup kan
thanks yg uda jwb
No.12,26,30 dan 33 itu kan sudut berpelurus. Jadi, jumlah sudut-sudut berpelurus itu 180⁰ yaa
12. <AOC = 2x
<COB = 121⁰24' = 121⁰ + 24/60⁰
= 121⁰ + 0,4⁰ = 121,4⁰
1 derajat = 60 menit
1⁰ = 60' ---------> 1' = 1/60⁰
<AOC + <COB = 180⁰
2x + 121,4⁰ = 180⁰
2x = 180⁰ - 121,4⁰
2x = 58,6⁰
x = 58,6⁰/2 = 29,3⁰
26. <ABD + <CBD = 180⁰
14x⁰ + 4x⁰ = 180⁰
18x⁰ = 180⁰
x = 180⁰/18⁰ = 10⁰
<CBD = 4x⁰ = 4.10⁰ = 40⁰
pelurus <CBD = 180⁰ - <CBD
= 180⁰ - 40⁰ = 140⁰( c. )
27. Jumlah sudut-sudut berpenyiku itu 90⁰ yaa
<SPR + <QPR = 90⁰
6x⁰ + 12x⁰ = 90⁰
18x⁰ = 90⁰
x⁰ = 90⁰/18⁰ = 5
<QPR = 12x = 12.5 = 60⁰
penyiku <QPR = 90⁰ - <QPR
= 90⁰ - 60⁰ = 30⁰( b. )
30. <ABE + <EBD + <DBC = 180⁰
4x⁰ + 8x⁰ + 6x⁰ = 180⁰
18x⁰ = 180⁰
x = 180⁰/18⁰ = 10
<ABE = 4x⁰ = 4.10⁰ = 40⁰
<EBD = 8x⁰ = 8.10⁰ = 80⁰
<DBC = 6x⁰ = 6.10⁰ = 60⁰
Ini kan ditanyakan beaar pelurus dari sudut tersebut, tapi ga dijelasin sudut yang mana itu
31. <KLN + <MLN = 180⁰
2x⁰ + ( 3x + 40⁰ ) = 180⁰
5x + 40⁰ = 180⁰
5x = 180⁰ - 40⁰
5x = 140⁰
x = 140⁰/5 = 28
<MLN = 3x + 40⁰
= 3.28 + 40⁰ = 84⁰ + 40⁰
= 124⁰( d. )
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